12 2025-08-14  Ö-Ralley 10
Herma Gutmann - Andrea Kogler
   

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Paar: 12    Herma Gutmann - Andrea Kogler

Score: 133,0    41,0 %    Platz: 13    
                         
Rnd  Tisch  Als  Geg  Board  Kont      Aus  Ergebnis  Score    %    Runde   %      Ges     %        Name d. Gegners

 1     4    O-W   4     10   5T   N -1 KA       -100    3,0   25                                    Heil - Kotyczka
                        11   2P   W -2 HB    100        0,0    0                                            
                        12   2N   S +1 KB    150        0,0    0      3,0   8      3,0   8,3                

 2     5    O-W   5     22   3T   N +1 KA    130        2,0   17                                    Lederer - Wendler
                        23   3K   S  = P7    110        4,0   33                                            
                        24   2P   W -2 HA    100        2,0   17      8,0  22     11,0  15,3                

 3     6    O-W   6     1    3T   W +1 P3       -130    8,0   67                                    Schuchlenz - Schuchlenz
                        2    3T   N  = PA    110        3,0   25                                            
                        3    4P   S -1 H10       -50    9,0   75     20,0  56     31,0  28,7                

 4     7    N-S   7     7    2K   S +2 PA    130        4,0   33                                    Six - Zimmermann
                        8    4H   N  = TA    420       10,0   83                                            
                        9    3H   S -1 KA        -50    4,0   33     18,0  50     49,0  34,0                

 5     8    O-W   13    13   2T   W  = PA        -90    4,0   33                                    Fuchs - Spörk
                        14   5P   S +1 K3    480        4,0   33                                            
                        15   1K   W  = HA        -70    6,0   50     14,0  39     63,0  35,0                

 6     8    N-S   11    16   3H   O  = P6       -140    0,0    0                                    Maldet - Maldet
                        17   3P   O +1 TB       -170   10,0   83                                            
                        18   4H   O  = TA       -420    9,0   75     19,0  53     82,0  38,0                

 7     1    O-W   1     19   4P   S +1 KB    450        0,0    0                                    Ehritz - Scheiber
                        20   3H   O +2 P9       -200    5,0   42                                            
                        21   2P   O +1 HD       -140    9,0   75     14,0  39     96,0  38,1                

 8     2    N-S   2     25   3N   N  = H5    400       10,0   83                                    Krajny - Siegl
                        26   1N   O -1 KK    100        8,0   67                                            
                        27   6H   S +1 T9   1010       10,0   83     28,0  78    124,0  43,1                

 9     3    N-S   3     4    4P   S -2 H2       -200    0,0    0                                    Heil - Moretti
                        5    3Px  S -1 TK       -200    0,0    0                                            
                        6    2H   O  = KA       -110    9,0   75      9,0  25    133,0  41,0                


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