3 2025-05-29  3.6.
Ferdinand Spörk - Heidi Zimmermann
   

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Paar: 3    Ferdinand Spörk - Heidi Zimmermann

Score: 190,1 *    58,7 %    Platz: 3    
                    
Rnd  Tisch  Als  Geg  Board  Kont      Aus  Ergebnis  Score    %    Runde    %      Ges      %        Name d. Gegners

 1     3    N-S   11    7    3N   O -2 P2    200       12,0  100                                      Kotyczka - Kovacs
                        8    3T   W +1 PA       -130    2,0   17                                            
                        9    5T   N  = P2    400        4,0   33     18,0   50     18,0   50,0              

 2     3    N-S   10    10   2N   S +1 PD    150        7,0   58                                      Ropposch - Schachner
                        11   3H   S  = K4    140        6,0   50                                            
                        12   4H   N +2 K9    680        2,5   21     15,5   43     33,5   46,5              

 3     3    N-S   9     13   3T   S +1 H3    130        6,0   50                                      Lederer - Wendler
                        14   3P   W +1 T8       -170    8,0   67                                            
                        15   2P   W +1 HA       -140    0,0    0     14,0   39     47,5   44,0              

 4     3    O-W   --    16                     Pause    7,0   59                                      Pause 
                        17                     Pause    7,0   59                                            
                        18                     Pause    7,0   59     21,1   59     68,6   47,7              

 5     3    N-S   16    19   2P   N +1 P2    140        8,0   67                                      Fenz - Schindlauer
                        20   3H   N +2 PK    200        4,0   33                                            
                        21   6N   W -1 H2     50       11,0   92     23,0   64     91,6   50,9              

 6     3    N-S   15    22   3H   N +1 KB    170       11,0   92                                      Maldet - Maldet
                        23   Pass              0       12,0  100                                            
                        24   4P   W  = KA       -420    1,0    8     24,0   67    115,6   53,5              

 7     3    N-S   14    25   1N   W -1 P10   100       11,0   92                                      Lackner - Nickl
                        26   3N   W -1 K3    100       12,0  100                                            
                        27   3H   N  = TA    140        2,5   21     25,5   71    141,1   56,0              

 8     3    O-W   13    1    2K   N +2 T7    130        4,0   33                                      Ehritz - Schober
                        2    1N   O -1 H3     50        9,0   75                                            
                        3    2N   O +1 K5       -150    9,0   75     22,0   61    163,1   56,6              

 9     3    O-W   12    4    2P   S -1 K2       -100    8,0   67                                      Daum - Scheiber
                        5    2P   S -1 KA       -100   10,0   83                                            
                        6    2P   W  = H4       -110    9,0   75     27,0   75    190,1   58,7              


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