17 2023-05-11  Ö-Ralley 4
Anita Marth - Ferdinand Spörk
   

Ergebnisliste  <<  >>  1  2  3  4  5  6  7  8  9  11  12  13  14  15  16  17  18  19

Paar: 17    Anita Marth - Ferdinand Spörk

Score: 221,8    51,3 %    Platz: 8    
                          
Rnd  Tisch  Als  Geg  Board  Kont     Aus  Ergebnis  Score    %    Runde    %      Ges      %        Name d. Gegners

 1     7    O-W   7     19   2N  O +1 HD       -150   16,0  100                                      Heil - Kotyczka
                        20   5T  N -1 P9       -100   15,0   94                                             
                        21   1Hx N -1 TA       -200   11,0   69     42,0   88     42,0   87,5               

 2     8    O-W   8     25   4P  O +2 HB       -680    3,0   19                                      Krajny - Siegl
                        26   2N  N +1 K5    150        5,0   31                                             
                        27   4H  W +1 T10      -450   13,0   81     21,0   44     63,0   65,6               

 3     9    O-W   9     4    4Px S -1 K6       -200    4,0   25                                      Gartner - Noe
                        5    4H  N +1 PA    650       16,0  100                                             
                        6    2P  N  = TK    110       12,0   75     32,0   67     95,0   66,0               

 4     1    O-W   1     10   5N  O -1 T4    100        4,0   25                                      Obendrauf - Tieber
                        11   2H  O  = P3       -110    3,0   19                                             
                        12   1H  W -1 KA     50        6,0   38     13,0   27    108,0   56,3               

 5     2    O-W   2     16   4H  S -1 T8        -50   15,0   94                                      Kaiba - Stranzl
                        17   3N  O -1 K6     50        1,0    6                                             
                        18   2K  S -1 T4       -100   16,0  100     32,0   67    140,0   58,3               

 6     3    N-S   3     22   4H  O +1 K5       -650    2,0   13                                      Fenz - Kovacs
                        23   3P  S -2 K5       -200    0,0    0                                             
                        24   2Tx S  = H2    180       16,0  100     18,0   38    158,0   54,9               

 7     4    O-W   4     1    3N  N +2 P9    460        0,0    0                                      Geyer - Schindlauer
                        2    3P  S -2 K2       -200   12,0   75                                             
                        3    3N  N +1 TA    430        0,0    0     12,0   25    170,0   50,6               

 8     5    N-S   5     7    3N  W  = T6       -600    2,0   13                                      Heil - Noe
                        8    5Hx O  = P5       -650    0,0    0                                             
                        9    3N  W -4 P6    400       16,0  100     18,0   38    188,0   49,0               

 9     6    N-S   6     13   3P  O  = T2       -140   14,0   88                                      Krenn - Rotter
                        14   2H  W  = PA       -110    5,8   36                                             
                        15   2H  W -4 PA    200       14,0   88     33,8   70    221,8   51,3               


Ergebnisliste  <<  >>  1  2  3  4  5  6  7  8  9  11  12  13  14  15  16  17  18  19